Find the Boolean expression and logic table for the following combinatorial circuit.

1 is true, 0 is false.

x y z x ∨ 1 ~y z ∧ 0 ~y ∨(z ∧ 0) (x ∨ 1) ∧ [~y ∨ (z ∧ 0)] ~{(x ∨ 1) ∧ [~y ∨ (z ∧ 0)]}
1 1 1            
1 1 0            
1 0 1            
1 0 0            
0 1 1            
0 1 0            
0 0 1            
0 0 0