order of statements

The different orders of statements show different output (displaying on screen).

public class Test { public static void main(String [] args) { int A = 10; System.out.println(A); A = A + 1; } }	public class Test { public static void main(String [] args) { int A = 10; A = A + 1; System.out.println(A); } }
After you run the above program, 10 will be on the screen. 11 is in memory box A, which you could not see.	After you run the above program, 11 is in memory box A, which you could not see. 11 will be on the screen.

The following statements take the same actions.

public class Test
{
public static void main(String [] args)
{
   int A = 10;
   A = A + 1;
   System.out.println(A);
}
} public class Test
{
public static void main(String [] args)
{
   int A = 10;
   A++;
   System.out.println(A);
}
} public class Test
{
public static void main(String [] args)
{
   int A = 10;
   ++A;
   System.out.println(A);
}
}

However, the short cut of two statements perform differently.

public class Test
{
public static void main(String [] args)
{
   int A = 10;
   System.out.println(A++);
}
}
//combine two statements
public class Test
{
public static void main(String [] args)
{
   int A = 10;
   System.out.println(++A);
}
}
//combine two statements

public class Test
{
public static void main(String [] args)
{
   int A = 10;
   System.out.println(A);
   A = A + 1;
}
} public class Test
{
public static void main(String [] args)
{
   int A = 10;
   A = A + 1;
   System.out.println(A);
}
}

What are output of the following two sets of programs?

public class Test
{
public static void main(String [] args)
{
   int A = 10;
   int B = 5;
   System.out.println(A++-B);
}
} public class Test
{
public static void main(String [] args)
{
   int A = 10;
   int B = 5;
   System.out.println(++A-B);
}
}